he formula to calculate the force on a current-carrying conductor in a magnetic field is:
\(F = BIL sinθ \)
Where,
B =\(B =\) magnetic field \(= 0.4 T \)
\(I =\) current \(= 2 A\)
\(L =\) length \(= 3 m \)
\(θ =\) angle \(= 30° \)
Substitute the values:
\(F = 0.4 × 2 × 3 × sin(30°) \)
\(F = 0.4 × 2 × 3 × 0.5 = 1.2 N\)
The correct answer is option (A): \(1.2 N\)