A force exerted on a 3 m long conductor having a current of 2 A in 0.4 T magnetic induction with an angle of 30° is
- 1.2 N
- 12 N
- 72 N
- 2.4 N
The Correct Option is A
Solution and Explanation
he formula to calculate the force on a current-carrying conductor in a magnetic field is:
\(F = BIL sinθ \)
Where,
B =\(B =\) magnetic field \(= 0.4 T \)
\(I =\) current \(= 2 A\)
\(L =\) length \(= 3 m \)
\(θ =\) angle \(= 30° \)
Substitute the values:
\(F = 0.4 × 2 × 3 × sin(30°) \)
\(F = 0.4 × 2 × 3 × 0.5 = 1.2 N\)
The correct answer is option (A): \(1.2 N\)
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