Question:

A drunkard walking in a narrow lane takes 8 steps forward and 6 steps backward, followed again by 8 steps forward and 6 steps backward and so on. Each step is 1 m long and requires 1 s. Determine how long the drunkard takes to fall in a pit 18 m away from the start

Updated On: Jul 5, 2022
  • 18 s
  • 126 s
  • 78 s
  • 62 s
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The Correct Option is C

Solution and Explanation

When the drunkard walks 8 steps forward and 6 steps backward, the displacement in the first 14 steps $= 8\, m - 6\, m = 2\, m$ Time taken for first 14 steps $= 14\, s$ Time taken by drunkard to cover first 10 m of journey $= \frac{14}{2}\times10 = 70\,s$ If the drunkard takes 8 steps more, he will fall into the pit, so the time taken by the last 8 steps $= 8 \,s$ Total time taken $= 70 \,s + 8\, s = 78\, s$
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Concepts Used:

Motion in a straight line

The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion. 

Types of Linear Motion:

Linear motion is also known as the Rectilinear Motion which are of two types:

  1. Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
  2. Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.