Question

‘A’ diploid chromosome number is 4. ‘B’ haploid chromosome number is twice to that of A. ‘C’ diploid chromosome number is thrice to that of A. A, B and C respectively are

• A. \( A = \text{Maize}, B = \text{House fly}, C = \text{Onion} \)
• B. \( A = \text{Housefly}, B = \text{Potato}, C = \text{Onion} \)
• C. \( A = \text{Haplopappus}, B = \text{House fly}, C = \text{Tomato} \)
• D. \( A = \text{Haplopappus}, B = \text{Onion}, C = \text{House fly} \)

Hint:

To solve chromosome number problems, it is important to understand the relationship between diploid and haploid numbers. In this case, using the given ratios for the haploid numbers of B and C with respect to A, we determined the correct matching of A, B, and C.

Answer 1

The Correct Option is D

Given that the diploid chromosome number of A is 4. Thus, the haploid number of A will be \( \frac{4}{2} = 2 \).
The haploid number of B is twice that of A, so the haploid number of B will be \( 2 \times 2 = 4 \). Therefore, the diploid number of B is \( 4 \times 2 = 8 \).
The diploid number of C is thrice that of A, so the diploid number of C is \( 4 \times 3 = 12 \).
Thus, we have the following: \[ A = \text{Haplopappus}, \quad B = \text{Onion}, \quad C = \text{House fly} \]