The given impulse response is \( h[n]=2^nu[n] \) which is a right sided sequence.
The z transform of \( a^n u[n] \) is given by \( \frac{1}{1-az^{-1}} \). Here \( a = 2 \)
Therefore, \(H(z) = \frac{1}{1-2z^{-1}}\) or \( H(z) = \frac{z}{z-2} \). For the sequence to be stable the ROC (region of convergence) must be outside the circle with radius 2. Therefore, it excludes the unit circle.