Step 1: Recall the effect of a dielectric.
When a dielectric material is inserted between the plates of a capacitor, it increases the capacitance by a factor of the dielectric constant (\( \kappa \)). For an isolated capacitor, the charge \(Q\) remains constant.
Step 2: Force between the plates.
The force \(F\) between the plates of a capacitor is given by:
\[
F = \frac{1}{2} \frac{Q^2}{A \epsilon_0} \left( \frac{1}{d^2} \right)
\]
When a dielectric is inserted, the electric field between the plates decreases, thus reducing the force between the plates.
Step 3: Conclusion.
Thus, the force between the plates will decrease.
Final Answer:
\[
\boxed{\text{decrease}}
\]