Question

A die is thrown once. Find the probability of getting 
(i) a prime number; 
(ii) a number lying between 2 and 6;
(iii) an odd number.

Answer 1

The possible outcomes when a dice is thrown = {1, 2, 3, 4, 5, 6}
Number of possible outcomes of a dice = 6

(i) Prime numbers on a dice are 2, 3, and 5.
Total prime numbers on a dice = 3 
Probability of getting a prime number =\( \frac{3}{6}=\frac{1}{2}\)

(ii) Numbers lying between 2 and 6 = 3, 4, 5
Total numbers lying between 2 and 6 = 3 
Probability of getting a number lying between 2 and 6 =\(\frac{3}{6}=\frac{1}{2}\)

(iii) Odd numbers on a dice = 1, 3, and 5 
Total odd numbers on a dice = 3 
Probability of getting an odd number =\(\frac{3}{6}=\frac{1}{2}.\)