The probability of not getting an odd number in a single throw is: \[ P(\text{not odd}) = \frac{3}{6} = \frac{1}{2}. \] The probability of not getting an odd number in 10 throws is: \[ \left(\frac{1}{2}\right)^{10} = \frac{1}{1024}. \] Thus, the probability of getting at least one odd number is: \[ 1 - \frac{1}{1024} = \frac{1023}{1024}. \]