Step 1: Use the formula for work done in an adiabatic process.
For an adiabatic expansion, the work done \( W \) by the gas is given by:
\[
W = n C_V \Delta T
\]
where \( n \) is the number of moles, \( C_V \) is the molar heat capacity at constant volume for a diatomic gas, and \( \Delta T \) is the change in temperature. For a diatomic gas, \( C_V = \frac{5}{2} R \), where \( R = 8.314 \, \text{J/mol·K} \) is the universal gas constant.
Step 2: Calculate the work done.
The temperature change is:
\[
\Delta T = 400 \, \text{K} - 1150 \, \text{K} = -750 \, \text{K}
\]
Now, substitute into the work equation:
\[
2300 \, \text{J} = n \times \frac{5}{2} \times 8.314 \times (-750)
\]
Solving for \( n \):
\[
n = \frac{2300}{\frac{5}{2} \times 8.314 \times (-750)} = 1.00 \, \text{mol}
\]
Step 3: Conclusion.
Thus, the number of moles required to obtain 2300 J of work from the expansion is 1.00 mol.