A cycle tube will burst if the volume of air inside exceeds 1L at the room temperature. If at I bar pressure the air occupies 500 mL, then up to what pressure can the tube be expanded at the same temperature?
- 2 bar
- 1.5 bar
1.2 bar
- 0.002 bar
0.5 bar
The Correct Option is
Solution and Explanation
To solve this problem, we use Boyle's Law, which states:
\( P_1 V_1 = P_2 V_2 \)
Given:
- \( P_1 = 1 \) bar
- \( V_1 = 500 \) mL = 0.5 L
- \( V_2 = 1 \) L (maximum volume)
We substitute the values into the formula:
\( 1 \times 0.5 = P_2 \times 1 \)
Solving for \( P_2 \):
\( P_2 = \frac{0.5}{1} = 0.5 \) bar
Final Answer:
0.5 bar
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