Question:
A current of strength $2.5$ amp was passed through $CuSO _{4}$ solution for 6 minutes $26$ seconds. The amount of copper deposited is :
(At. wt. of $Cu =63.5,1\, F =96500$ coulomb $)$
A current of strength $2.5$ amp was passed through $CuSO _{4}$ solution for 6 minutes $26$ seconds. The amount of copper deposited is :
(At. wt. of $Cu =63.5,1\, F =96500$ coulomb $)$
Updated On: Jun 23, 2023
- 0.3175 g
- 3.175 g
- 0.635 g
- 6.35 g
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The Correct Option is A
Solution and Explanation
Number of coulombs passed $=i \times t$
$t=6 \times 60+26=360+26$
$=386$ seconds
$=2.5 \times 386=965$
$2 \times 96500 C$ charge deposits $=63.5 g$
$1\, C$ charge deposits $=\frac{63.5}{2 \times 96500}$
$965\, C$ charge deposits $=\frac{63.5 \times 965}{2 \times 96500}$
$=0.3175\, g$
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Concepts Used:
Electrolysis
Electrolysis:
Electrolysis is the process by which an element is decomposed and undergoes some chemical change under the influence of any electric current. The first-ever electrolysis was executed out by Sir Humphrey Davey in the year 1808. Electrolysis can occur in both Galvanic cells and Electrolytic cells.
Applications of Electrolysis:
- Electrolytic cells are used for the production of Hydrogen and Oxygen gas from water.
- They are used for the large-scale production of pure metals like sodium, copper, magnesium, etc.
- They are used to extract Aluminium from Bauxite.
- Electrolytic cells are used for electroplating, a process by which a thin protective layer of one metal is formed over another metal, mostly for protection.
- Electrolysis is used for the electrorefining of non-ferrous metals.
Read More: Products of Electrolysis