We have the cricket ball having amass of 0.25 kg and moving with a speed of 10$ ms^{-1}$, so the change in momentum would be equal to $\Delta p = 2mv = 2\times 0.25 \times 10 = 5kg-ms^{-1}$ and thus the force would be equal to F $\frac{\Delta p}{\Delta t}=\frac{5}{0.01}=500 N$