Question:

A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days \(\frac{4}{7}\) of the work is completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day?

Updated On: Oct 4, 2024
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The Correct Option is B

Solution and Explanation

The correct option is (B); Formula = \(\frac{ M_{1} D_{1}H_{1}}{ W_{1} }\)=\(\frac{ M_{2} D_{2}H_{2}}{ W_{2} }\)
117 men completed \(\frac{4}{7}\) work in 33 days working 8 hours per day.
Let \(x\) men complete the remaining \(\frac{3}{7}\) work in 13 days working 9 hours per day.
\( \frac{177\times33\times8}{4}\)=\( \frac{x\times13\times9}{3}\)
\(x = 33\times2\times3\) = 198
\(\therefore\) Additional mens are 198-117 = 81
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