A constant torque of $31.4\, Nm$ is exerted on a pivoted wheel. If angular acceleration of wheel is $4\pi\,rad\,s^{-2}$, then the moment of inertia of w heel is
Updated On: Jul 5, 2022
$3.5\,kg\,m^2$
$2.5\,kg\,m^2$
$4.5\,kg\,m^2$
$5.5\,kg\,m^2$
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The Correct Option isB
Solution and Explanation
$I \alpha = \tau \, i.e. \, I = \frac{\tau}{\alpha} = \frac{31.4}{4 \pi} = 2.5 \, kg \, m^2$
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