The average power delivered by a force is given by the formula: \[ P_{{avg}} = \frac{{Work Done}}{{Time Taken}} = \frac{F \cdot d}{t} \]
where:
- \(F = 6 \, {N}\) (force),
- \(d = 3 \, {m}\) (displacement),
- \(t = 2 \, {s}\) (time).
Substituting the values: \[ P_{{avg}} = \frac{6 \times 3}{2} = 9 \, {W} \]
Hence, the correct answer is (D).
If the voltage across a bulb rated 220V – 60W drops by 1.5% of its rated value, the percentage drop in the rated value of the power is: