Magnification produced by a spherical mirror is given by the relation,
\(m=\frac{\text{Height of the image}}{\text{Height of the object}}\)
\(=-\frac{\text{Image distance}}{\text{Object distance}}\)
\(⇒ m=\frac{h_I}{h_o}=\frac{-v}{u}\)
Let the height of the object,\( h_o = h \)
Then, height of the image,\( h_I = −3h\) (Image formed is real)
\(-\frac{3h}{h}=\frac{-v}{u}\)
\(⇒\frac{v}{u}=3.\)
Object distance, u = −10 cm
v = 3 × (−10) = −30 cm
Here, the negative sign indicates that an inverted image is formed at a distance of 30 cm in front of the given concave mirror.
On the day of her examination, Riya sharpened her pencil from both ends as shown below. 
The diameter of the cylindrical and conical part of the pencil is 4.2 mm. If the height of each conical part is 2.8 mm and the length of the entire pencil is 105.6 mm, find the total surface area of the pencil.
