Question:
A compound \( X \) on heating gives a colourless gas. The residue is dissolved in water to obtain \( Y \). Excess \( CO_2 \) is passed through aqueous solution of \( Y \) when \( Z \) is formed. \( Z \) on gentle heating gives back \( X \). The compound \( X \) is
A compound \( X \) on heating gives a colourless gas. The residue is dissolved in water to obtain \( Y \). Excess \( CO_2 \) is passed through aqueous solution of \( Y \) when \( Z \) is formed. \( Z \) on gentle heating gives back \( X \). The compound \( X \) is
Show Hint
The decomposition of calcium bicarbonate leads to calcium carbonate, which can be re-dissolved and react with \( CO_2 \).
Updated On: Jan 12, 2026
- \( Ca(HCO_3)_2 \)
- \( CaCO_3 \)
- \( Na_2CO_3 \)
- \( Na_2CO_3 \)
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
The compound \( X \) is \( Ca(HCO_3)_2 \), which on heating decomposes to form calcium carbonate and carbon dioxide, and the reaction steps match with the given description.
Was this answer helpful?
0
0
Top Questions on Solutions
- Consider the dissociation equilibrium of the following weak acid: \[ \mathrm{HA \rightleftharpoons H^+(aq) + A^-(aq)} \] If the \(pK_a\) of the acid is \(4\), then the pH of a \(10\ \text{mM}\) HA solution is ________ (Nearest integer). (Given: The degree of dissociation can be neglected with respect to unity)
- The crystal field splitting energy of $[Co(oxalate)_3]^3-$ complex is 'n' times that of the $[Cr(oxalate)_3]^3-$ complex. Here 'n' is_______ (Assume $\Delta_0 > P$)}
- The osmotic pressure of a living cell is 12 atm at 300 K. The strength of sodium chloride solution that is isotonic with the living cell at this temperature is ____________ g L$^{-1}$. (Nearest integer)
Given: R = 0.08 L atm K$^{-1}$ mol$^{-1}$
Assume complete dissociation of NaCl
(Given : Molar mass of Na and Cl are 23 and 35.5 g mol$^{-1}$ respectively.) A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.- At \(T\) K, \(100\,\text{g}\) of \(98%\) \(H_2SO_4\) (w/w) aqueous solution is mixed with \(100\,\text{g}\) of \(49%\) \(H_2SO_4\) (w/w) aqueous solution. What is the mole fraction of \(H_2SO_4\) in the resultant solution? (Given: Atomic mass \(H = 1\,u,\; S = 32\,u,\; O = 16\,u\). Assume that temperature after mixing remains constant.)
View More Questions
Questions Asked in VITEEE exam
- Find the value of \( x \) in the following equation: \[ \frac{2}{x} + \frac{3}{x + 1} = 1 \]
- VITEEE - 2025
- Algebra
- How many numbers between 0 and 9 look the same when observed in a mirror?
- VITEEE - 2025
- Odd one Out
- In a code language, 'TIGER' is written as 'JUISF'. How will 'EQUAL' be written in that language?
- VITEEE - 2025
- Odd one Out
- In a code language, 'TIGER' is written as 'JUISF'. How will 'EQUAL' be written in that language?
- VITEEE - 2025
- Data Interpretation
- TUV : VYB :: PRA : ?
- VITEEE - 2025
- Odd one Out
View More Questions