Question:
A compound of $'A'$ and $'B'$ crystallises in a cubic lattice in which the $'A'$ atoms occupy the lattice points at the corners of the cube. The $'B'$ atoms occupy the centre of each face of the cube. The probable empirical formula of the compound is
A compound of $'A'$ and $'B'$ crystallises in a cubic lattice in which the $'A'$ atoms occupy the lattice points at the corners of the cube. The $'B'$ atoms occupy the centre of each face of the cube. The probable empirical formula of the compound is
Updated On: Apr 14, 2024
- $AB$
- $AB_3$
- $AB_2$
- $A_3B$
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The Correct Option is B
Solution and Explanation
A occupies corners, thus number of $A$ atoms per unit cell $=8 \times \frac{1}{8}=1$
$B$ occupies face centres, thus number of $B$ atoms per unit cell $=6 \times \frac{1}{2}=3$
$\therefore$ The empirical formula of the compound is $A B_{3} .$
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Concepts Used:
Solid State
Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions.
Types of Solids:
Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;
- Amorphous solids behave the same as super cool liquids due to the arrangement of constituent particles in short-range order. They are isotropic and have a broad melting point (range is about greater than 5°C).
- Crystalline solids have a fixed shape and the constituent particles are arranged in a long-range order.