Question:

A compass needle whose magnetic moment is $60\, A \,m^2$ pointing geographical north at a certain place where the horizontal component of earth?s magnetic field is $40 \times 10^{-6}\, Wb\, m^{-2}$ experiences a torque of $1.2 \times 10^{-3}\, N\, m$. The declination of the place is

Updated On: Jun 23, 2023
  • $20^{\circ}$
  • $45^{\circ}$
  • $60^{\circ}$
  • $30^{\circ}$
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The Correct Option is D

Solution and Explanation

In stable equilibrium, a compass needle points along magnetic north and experiences no torque. When it is turned through declination $\alpha$, it points along geographic north and experiences torque, $\tau = mB \,sin\alpha$ $\therefore\quad sin\,\alpha = \frac{\tau}{mB} $ $= \frac{1.2 \times 10^{-3}}{60 \times 40 \times 10^{-6}} $ $= \frac{1}{2}$ or $\alpha = 30^{\circ}$
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Concepts Used:

Magnetism & Matter

Magnets are used in many devices like electric bells, telephones, radio, loudspeakers, motors, fans, screwdrivers, lifting heavy iron loads, super-fast trains, especially in foreign countries, refrigerators, etc.

Magnetite is the world’s first magnet. This is also called a natural magnet.  Though magnets occur naturally, we can also impart magnetic properties to a substance. It would be an artificial magnet in that case.

Read More: Magnetism and Matter

Some of the properties of the magnetic field lines are:

  • The lines and continuous and outside the magnet, the field lines originate from the North pole and terminate at the South pole
  • They form closed loops traversing inside the magnet. 
  • But here the lines seem to originate from the South pole and terminate at the North pole to form closed loops.
  • More number of close lines indicate a stronger magnetic field
  • The lines do not intersect each other
  • The tangent drawn at the field line gives the direction of the field at that point.