Comprehension
A company manufactured cups of four different types. The table given below shows the number of cups of four different types manufactured by the company in four different weeks of a month.
The number of cups of type D manufactured in week IV is 480 less than the number of cups of type A manufactured in week I. The number of cups of type C manufactured in week II is 1/6 of the total number of the cups of type B manufactured. The number of cups of type A manufactured in week III is 220 more than the number of cups of type B manufactured in week I.
| Types | Week I | Week II | Week III | Week IV | Total |
| Type A | 2650 | 1640 | - | - | 8820 |
| Type B | - | 1520 | 1650 | 1730 | - |
| Type C | 3240 | - | - | 2550 | 8750 |
| Type D | 2960 | 1220 | - | - | 8270 |
| Total | 10730 | - | 7530 | - | - |
Question: 1
What is the number of cups of type A manufactured in week IV ?
What is the number of cups of type A manufactured in week IV ?
Updated On: Sep 10, 2024
- 2570
- 2360
- 2210
- 2430
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
The number of cups of type B manufactured in week I = 10730 - 2650 - 3240 - 2960 = 1880
The total number of cups of type B manufactured =1880 + 1520 + 1650 + 1730 = 6780
The number of cups of type C manufacture in week II = 6780 × \(\frac{1}{6}\) = 1130
The total number of cups of all types manufactured in week II = 1640 + 1520 + 1130 + 1220 = 5510
The number of cups of type A manufactured in week III = 1880 + 220 = 2100
The number of cups of type A manufactured in week IV = 8820 - 2650 - 1640 - 2100 = 2430
The number of cups of type D manufactured in week IV = 2650 - 480 = 2170
The number of cups of type C manufactured in week III = 8780 - 3240 - 1130 - 2550 = 1860
The number of cups of type D manufactured in week III = 8270-2960 - 1220 - 2170 = 1920
The total number of cups of all types manufactured in week IV = 2430 +1730 + 2550 + 2170 = 8880
Required number of cups of type A manufactured in week IV = 2430
So, the correct option is (D) : 2430.
The total number of cups of type B manufactured =1880 + 1520 + 1650 + 1730 = 6780
The number of cups of type C manufacture in week II = 6780 × \(\frac{1}{6}\) = 1130
The total number of cups of all types manufactured in week II = 1640 + 1520 + 1130 + 1220 = 5510
The number of cups of type A manufactured in week III = 1880 + 220 = 2100
The number of cups of type A manufactured in week IV = 8820 - 2650 - 1640 - 2100 = 2430
The number of cups of type D manufactured in week IV = 2650 - 480 = 2170
The number of cups of type C manufactured in week III = 8780 - 3240 - 1130 - 2550 = 1860
The number of cups of type D manufactured in week III = 8270-2960 - 1220 - 2170 = 1920
The total number of cups of all types manufactured in week IV = 2430 +1730 + 2550 + 2170 = 8880
| Types | Week I | Week II | Week III | Week IV | Total |
| Type A | 2650 | 1640 | 2100 | 2430 | 8820 |
| Type B | 1880 | 1520 | 1650 | 1730 | 6780 |
| Type C | 3240 | 1130 | 1860 | 2550 | 8780 |
| Type D | 2960 | 1220 | 1920 | 2170 | 8270 |
| Total | 10730 | 5510 | 7530 | 8880 | 32650 |
So, the correct option is (D) : 2430.
Was this answer helpful?
0
0
Question: 2
What is the ratio of the number of cups of type B manufactured in week I to the number of cups of type C manufactured in week III ?
What is the ratio of the number of cups of type B manufactured in week I to the number of cups of type C manufactured in week III ?
Updated On: Sep 10, 2024
- 94 : 93
- 87 : 85
- 80 : 79
- 90 : 87
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
The number of cups of type B manufactured in week I = 10730 - 2650 - 3240 - 2960 = 1880
The total number of cups of type B manufactured =1880 + 1520 + 1650 + 1730 = 6780
The number of cups of type C manufacture in week II = 6780 × \(\frac{1}{6}\) = 1130
The total number of cups of all types manufactured in week II = 1640 + 1520 + 1130 + 1220 = 5510
The number of cups of type A manufactured in week III = 1880 + 220 = 2100
The number of cups of type A manufactured in week IV = 8820 - 2650 - 1640 - 2100 = 2430
The number of cups of type D manufactured in week IV = 2650 - 480 = 2170
The number of cups of type C manufactured in week III = 8780 - 3240 - 1130 - 2550 = 1860
The number of cups of type D manufactured in week III = 8270-2960 - 1220 - 2170 = 1920
The total number of cups of all types manufactured in week IV = 2430 +1730 + 2550 + 2170 = 8880
Required ratio = 1880 : 1860 = 94 : 93
So, the correct option is (A) : 94 : 93.
The total number of cups of type B manufactured =1880 + 1520 + 1650 + 1730 = 6780
The number of cups of type C manufacture in week II = 6780 × \(\frac{1}{6}\) = 1130
The total number of cups of all types manufactured in week II = 1640 + 1520 + 1130 + 1220 = 5510
The number of cups of type A manufactured in week III = 1880 + 220 = 2100
The number of cups of type A manufactured in week IV = 8820 - 2650 - 1640 - 2100 = 2430
The number of cups of type D manufactured in week IV = 2650 - 480 = 2170
The number of cups of type C manufactured in week III = 8780 - 3240 - 1130 - 2550 = 1860
The number of cups of type D manufactured in week III = 8270-2960 - 1220 - 2170 = 1920
The total number of cups of all types manufactured in week IV = 2430 +1730 + 2550 + 2170 = 8880
| Types | Week I | Week II | Week III | Week IV | Total |
| Type A | 2650 | 1640 | 2100 | 2430 | 8820 |
| Type B | 1880 | 1520 | 1650 | 1730 | 6780 |
| Type C | 3240 | 1130 | 1860 | 2550 | 8780 |
| Type D | 2960 | 1220 | 1920 | 2170 | 8270 |
| Total | 10730 | 5510 | 7530 | 8880 | 32650 |
So, the correct option is (A) : 94 : 93.
Was this answer helpful?
0
0
Question: 3
Find the total number of cups of all types manufactured in week II.
Find the total number of cups of all types manufactured in week II.
Updated On: Sep 10, 2024
- 5260
- 5510
- 5780
- 5920
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
The number of cups of type B manufactured in week I = 10730 - 2650 - 3240 - 2960 = 1880
The total number of cups of type B manufactured =1880 + 1520 + 1650 + 1730 = 6780
The number of cups of type C manufacture in week II = 6780 × \(\frac{1}{6}\) = 1130
The total number of cups of all types manufactured in week II = 1640 + 1520 + 1130 + 1220 = 5510
The number of cups of type A manufactured in week III = 1880 + 220 = 2100
The number of cups of type A manufactured in week IV = 8820 - 2650 - 1640 - 2100 = 2430
The number of cups of type D manufactured in week IV = 2650 - 480 = 2170
The number of cups of type C manufactured in week III = 8780 - 3240 - 1130 - 2550 = 1860
The number of cups of type D manufactured in week III = 8270-2960 - 1220 - 2170 = 1920
The total number of cups of all types manufactured in week IV = 2430 +1730 + 2550 + 2170 = 8880
Required total number of cups of all types manufactured in week II = 5510
So, the correct option is (B) : 5510.
The total number of cups of type B manufactured =1880 + 1520 + 1650 + 1730 = 6780
The number of cups of type C manufacture in week II = 6780 × \(\frac{1}{6}\) = 1130
The total number of cups of all types manufactured in week II = 1640 + 1520 + 1130 + 1220 = 5510
The number of cups of type A manufactured in week III = 1880 + 220 = 2100
The number of cups of type A manufactured in week IV = 8820 - 2650 - 1640 - 2100 = 2430
The number of cups of type D manufactured in week IV = 2650 - 480 = 2170
The number of cups of type C manufactured in week III = 8780 - 3240 - 1130 - 2550 = 1860
The number of cups of type D manufactured in week III = 8270-2960 - 1220 - 2170 = 1920
The total number of cups of all types manufactured in week IV = 2430 +1730 + 2550 + 2170 = 8880
| Types | Week I | Week II | Week III | Week IV | Total |
| Type A | 2650 | 1640 | 2100 | 2430 | 8820 |
| Type B | 1880 | 1520 | 1650 | 1730 | 6780 |
| Type C | 3240 | 1130 | 1860 | 2550 | 8780 |
| Type D | 2960 | 1220 | 1920 | 2170 | 8270 |
| Total | 10730 | 5510 | 7530 | 8880 | 32650 |
So, the correct option is (B) : 5510.
Was this answer helpful?
0
0
Question: 4
What is the number of cups of type D manufactured in week III ?
What is the number of cups of type D manufactured in week III ?
Updated On: Sep 10, 2024
- 2110
- 2050
- 1840
- 1920
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
The number of cups of type B manufactured in week I = 10730 - 2650 - 3240 - 2960 = 1880
The total number of cups of type B manufactured =1880 + 1520 + 1650 + 1730 = 6780
The number of cups of type C manufacture in week II = 6780 × \(\frac{1}{6}\) = 1130
The total number of cups of all types manufactured in week II = 1640 + 1520 + 1130 + 1220 = 5510
The number of cups of type A manufactured in week III = 1880 + 220 = 2100
The number of cups of type A manufactured in week IV = 8820 - 2650 - 1640 - 2100 = 2430
The number of cups of type D manufactured in week IV = 2650 - 480 = 2170
The number of cups of type C manufactured in week III = 8780 - 3240 - 1130 - 2550 = 1860
The number of cups of type D manufactured in week III = 8270-2960 - 1220 - 2170 = 1920
The total number of cups of all types manufactured in week IV = 2430 +1730 + 2550 + 2170 = 8880
Required number of cups of type D manufactured in week III = 1920
So, the correct option is (D) : 1920.
The total number of cups of type B manufactured =1880 + 1520 + 1650 + 1730 = 6780
The number of cups of type C manufacture in week II = 6780 × \(\frac{1}{6}\) = 1130
The total number of cups of all types manufactured in week II = 1640 + 1520 + 1130 + 1220 = 5510
The number of cups of type A manufactured in week III = 1880 + 220 = 2100
The number of cups of type A manufactured in week IV = 8820 - 2650 - 1640 - 2100 = 2430
The number of cups of type D manufactured in week IV = 2650 - 480 = 2170
The number of cups of type C manufactured in week III = 8780 - 3240 - 1130 - 2550 = 1860
The number of cups of type D manufactured in week III = 8270-2960 - 1220 - 2170 = 1920
The total number of cups of all types manufactured in week IV = 2430 +1730 + 2550 + 2170 = 8880
| Types | Week I | Week II | Week III | Week IV | Total |
| Type A | 2650 | 1640 | 2100 | 2430 | 8820 |
| Type B | 1880 | 1520 | 1650 | 1730 | 6780 |
| Type C | 3240 | 1130 | 1860 | 2550 | 8780 |
| Type D | 2960 | 1220 | 1920 | 2170 | 8270 |
| Total | 10730 | 5510 | 7530 | 8880 | 32650 |
So, the correct option is (D) : 1920.
Was this answer helpful?
0
0
Question: 5
What is the difference between the total number of cups of type B manufactured in all the weeks together, and the total number of cups of all types manufactured in week IV ?
What is the difference between the total number of cups of type B manufactured in all the weeks together, and the total number of cups of all types manufactured in week IV ?
Updated On: Sep 10, 2024
- 2450
- 2100
- 2320
- 2430
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
The number of cups of type B manufactured in week I = 10730 - 2650 - 3240 - 2960 = 1880
The total number of cups of type B manufactured =1880 + 1520 + 1650 + 1730 = 6780
The number of cups of type C manufacture in week II = 6780 × \(\frac{1}{6}\) = 1130
The total number of cups of all types manufactured in week II = 1640 + 1520 + 1130 + 1220 = 5510
The number of cups of type A manufactured in week III = 1880 + 220 = 2100
The number of cups of type A manufactured in week IV = 8820 - 2650 - 1640 - 2100 = 2430
The number of cups of type D manufactured in week IV = 2650 - 480 = 2170
The number of cups of type C manufactured in week III = 8780 - 3240 - 1130 - 2550 = 1860
The number of cups of type D manufactured in week III = 8270-2960 - 1220 - 2170 = 1920
The total number of cups of all types manufactured in week IV = 2430 +1730 + 2550 + 2170 = 8880
Required differences = 8880 - 6780 = 2100
So, the correct option is (B) : 2100.
The total number of cups of type B manufactured =1880 + 1520 + 1650 + 1730 = 6780
The number of cups of type C manufacture in week II = 6780 × \(\frac{1}{6}\) = 1130
The total number of cups of all types manufactured in week II = 1640 + 1520 + 1130 + 1220 = 5510
The number of cups of type A manufactured in week III = 1880 + 220 = 2100
The number of cups of type A manufactured in week IV = 8820 - 2650 - 1640 - 2100 = 2430
The number of cups of type D manufactured in week IV = 2650 - 480 = 2170
The number of cups of type C manufactured in week III = 8780 - 3240 - 1130 - 2550 = 1860
The number of cups of type D manufactured in week III = 8270-2960 - 1220 - 2170 = 1920
The total number of cups of all types manufactured in week IV = 2430 +1730 + 2550 + 2170 = 8880
| Types | Week I | Week II | Week III | Week IV | Total |
| Type A | 2650 | 1640 | 2100 | 2430 | 8820 |
| Type B | 1880 | 1520 | 1650 | 1730 | 6780 |
| Type C | 3240 | 1130 | 1860 | 2550 | 8780 |
| Type D | 2960 | 1220 | 1920 | 2170 | 8270 |
| Total | 10730 | 5510 | 7530 | 8880 | 32650 |
So, the correct option is (B) : 2100.
Was this answer helpful?
0
0
Top Questions on Division Of Fractions
- In a forest there are as many Santa Trees as there are Ajanta Trees. One-fourth of all the tree are old. One-half of the total trees are in flowering stage. Which of the following statement is true?
- NMAT
- Quantitative Aptitude
- Division Of Fractions
- Find the area of rectangle whose length is 5.7cm and breadth is 3 cm.
- CBSE Class VII
- Mathematics
- Division Of Fractions
- Find:
(i) 0.2 × 6
(ii) 8 × 4.6
(iii) 2.71 × 5
(iv) 20.1 × 4
(v) 0.05 × 7
(vi) 211.02 × 4
(vii) 2 × 0.86- CBSE Class VII
- Mathematics
- Division Of Fractions
- Find:
(i) \(\frac{2}{5}\) ÷ \(\frac{1}{2}\)
(ii) \(\frac{4}{9}\) ÷ \(\frac{2}{3}\)
(iii) \(\frac{3}{7}\) ÷ \(\frac{8}{7}\)
(iv) 2\(\frac{1}{3}\)÷ \(\frac{3}{5}\)
(v) 3 \(\frac{1}{2}\) ÷ \(\frac{8}{3}\)
(vi) \(\frac{2}{5}\) ÷ 1 \(\frac{1}{2}\)
(vii) 3 \(\frac{1}{5}\) ÷ 1 \(\frac{2}{3}\)
(viii) 2 \(\frac{1}{5}\) ÷ 1 \(\frac{1}{5}\)- CBSE Class VII
- Mathematics
- Division Of Fractions
- Find:
(i) \(\frac{7}{3}\) ÷ 2
(ii)\(\frac{4}{9}\)÷ 5
(iii)\(\frac{6}{13}\) ÷ 7
(iv)4\(\frac{1}{3}\) ÷ 3
(v)3\(\frac{1}{2}\) ÷ 4
(vi)4\(\frac{3}{7}\) ÷ 7- CBSE Class VII
- Mathematics
- Division Of Fractions
View More Questions
Questions Asked in CAT exam
- The sum of all real values of $k$ for which $(\frac{1}{8})^k \times (\frac{1}{32768})^{\frac{4}{3}} = \frac{1}{8} \times (\frac{1}{32768})^{\frac{k}{3}}$ is
- CAT - 2024
- Logarithms
- Amal and Vimal together can complete a task in 150 days, while Vimal and Sunil together can complete the same task in 100 days. Amal starts working on the task and works for 75 days, then Vimal takes over and works for 135 days. Finally, Sunil takes over and completes the remaining task in 45 days. If Amal had started the task alone and worked on all days, Vimal had worked on every second day, and Sunil had worked on every third day, then the number of days required to complete the task would have been
- CAT - 2024
- Time and Work
- Gopi marks a price on a product in order to make 20% profit. Ravi gets 10% discount on this marked price, and thus saves Rs 15. Then, the profit, in rupees, made by Gopi by selling the product to Ravi, is
- CAT - 2024
- Profit and Loss
- Sam can complete a job in 20 days when working alone. Mohit is twice as fast as Sam and thrice as fast as Ayana in the same job. They undertake a job with an arrangement where Sam and Mohit work together on the first day, Sam and Ayana on the second day, Mohit and Ayana on the third day, and this three-day pattern is repeated till the work gets completed. Then, the fraction of total work done by Sam is
- CAT - 2024
- Time and Work
- The number of all positive integers up to 500 with non-repeating digits is
- CAT - 2024
- Number Systems
View More Questions