Question

A coin is tossed 6 times. What is the probability of getting head at least once?

• A. \( \frac{33}{64} \)
• B. \( \frac{27}{64} \)
• C. \( \frac{1}{64} \)
• D. \( \frac{63}{64} \)

Hint:

To calculate the probability of an event happening at least once, subtract the probability of the event not happening from (1)

Answer 1

The Correct Option is D

The probability of not getting a head in a single toss is \( \frac{1}{2} \). Therefore, the probability of not getting a head in all 6 tosses is: \[ P(\text{no heads in 6 tosses}) = \left( \frac{1}{2} \right)^6 = \frac{1}{64}. \] Thus, the probability of getting at least one head is: \[ P(\text{at least one head}) = 1 - P(\text{no heads}) = 1 - \frac{1}{64} = \frac{63}{64}. \]