A closely wounded circular coil of radius 5 cm produces a magnetic field of 37.68×10–4 T at its center. The current through the coil is _______ A.
[Given, number of turns in the coil is 100 and \(\pi = 3.14\)]
[Given, number of turns in the coil is 100 and \(\pi = 3.14\)]
Correct Answer: 3
Solution and Explanation
\(B = \frac{\mu_0 n I}{2R}\)
\(37.68 \times 10^{-4} = \frac{4\pi \times 10^{-7} \times 100I}{2 \times 5 \times 10^{-2}}\)
\(I = \frac{300\, \text{A}}{100}\)
\(I= 3A\)
So, the answer is 3A.
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter