Question:
A closely wounded circular coil of radius 5 cm produces a magnetic field of 37.68×10–4 T at its center. The current through the coil is _______ A.
[Given, number of turns in the coil is 100 and \(\pi = 3.14\)]
A closely wounded circular coil of radius 5 cm produces a magnetic field of 37.68×10–4 T at its center. The current through the coil is _______ A.
[Given, number of turns in the coil is 100 and \(\pi = 3.14\)]
[Given, number of turns in the coil is 100 and \(\pi = 3.14\)]
Updated On: Mar 19, 2025
Hide Solution
Verified By Collegedunia
Correct Answer: 3
Solution and Explanation
\(B = \frac{\mu_0 n I}{2R}\)
\(37.68 \times 10^{-4} = \frac{4\pi \times 10^{-7} \times 100I}{2 \times 5 \times 10^{-2}}\)
\(I = \frac{300\, \text{A}}{100}\)
\(I= 3A\)
So, the answer is 3A.
Was this answer helpful?
3
0
Top Questions on Electromagnetic induction
- You are required to design an air-filled solenoid of inductance 0.016 H having a length 0.81 m and radius 0.02 m. The number of turns in the solenoid should be:
- CBSE CLASS XII - 2025
- Physics
- Electromagnetic induction
- A metal rod of length 50 cm is held vertically and moved with a velocity in a magnetic field at the place of 0.4 G. The emf induced across the ends of the rod is:
- CBSE CLASS XII - 2025
- Physics
- Electromagnetic induction
- Consider two long co-axial solenoids \( S_1 \) and \( S_2 \), each of length \( l \) (\( l \gg r_2 \)) and radius \( r_1 \) and \( r_2 \) (\( r_2>r_1 \)). The number of turns per unit length are \( n_1 \) and \( n_2 \), respectively. Derive an expression for mutual inductance \( M_{12} \) of solenoid \( S_1 \) with respect to solenoid \( S_2 \). Show that \( M_{21} = M_{12} \).
- CBSE CLASS XII - 2025
- Physics
- Electromagnetic induction
- The current through an inductor is uniformly increased from zero to 2 A in 40 s. An emf of 5 mV is induced during this period. Find the flux linked with the inductor at t = 10 s.
- CBSE CLASS XII - 2025
- Physics
- Electromagnetic induction
- Two coils of copper wire are placed closer to each other. Due to change in the value of current in one coil, current starts to flow in the other coil. Reason for this phenomenon is -
- UP Board X - 2025
- Science
- Electromagnetic induction
View More Questions
Questions Asked in JEE Main exam
- A group 15 element forms \( d\pi - d\pi \) bond with transition metals. It also forms a hydride, which is the strongest base among the hydrides of other group members that form \( d\pi - d\pi \) bonds. The atomic number of the element is ________________________.
- JEE Main - 2025
- Chemical bonding and molecular structure
- The value of \( (\sin 70^\circ)(\cot 10^\circ \cot 70^\circ - 1) \) is:
- JEE Main - 2025
- Trigonometric Identities
- Match List-I with List-II.
- JEE Main - 2025
- Dimensional analysis
Nature of compounds TeO₂ and TeH₂ is___________ and ______________respectively.
- JEE Main - 2025
- Inorganic chemistry
- Let \( A = [a_{ij}] \) be a matrix of order 3 \(\times\) 3, with \(a_{ij} = (\sqrt{2})^{i+j}\). If the sum of all the elements in the third row of \( A^2 \) is \( \alpha + \beta\sqrt{2} \), where \(\alpha, \beta \in \mathbb{Z}\), then \(\alpha + \beta\) is equal to:
- JEE Main - 2025
- Matrices and Determinants
View More Questions
Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter