\(B = \frac{\mu_0 n I}{2R}\)
\(37.68 \times 10^{-4} = \frac{4\pi \times 10^{-7} \times 100I}{2 \times 5 \times 10^{-2}}\)
\(I = \frac{300\, \text{A}}{100}\)
\(I= 3A\)
So, the answer is 3A.
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where