Step 1: First overtone frequencies.
For closed organ pipe, first overtone corresponds to 3rd harmonic:
\[
f_c = \frac{3v}{4L_c}
\]
For open organ pipe, first overtone corresponds to 2nd harmonic:
\[
f_o = \frac{v}{L_o}
\]
Step 2: Equate frequencies.
\[
\frac{3v}{4L_c} = \frac{v}{L_o}
\]
Step 3: Find ratio of lengths.
\[
\frac{L_c}{L_o} = \frac{3}{4}
\]