Let the average score of the boys in the mid-semester exam be \( x \). Therefore, the average score of the girls in the mid-semester exam is \( x + 5 \). The total score for boys = \( 20x \) and for girls = \( 30(x + 5) = 30x + 150 \). The average of the entire class in the mid-semester exam is \(\frac{20x + 30x + 150}{50} = x + 3\).
In the final exam, the average score of the girls becomes \(x + 5 - 3 = x + 2\). The entire class's average increases by 2, so it is now \(x + 3 + 2 = x + 5\).
Total score in the final exam is \(\frac{50(x + 5)}{1}= 50x + 250\). The new total score for girls is \(30(x + 2) = 30x + 60\).
The total score for boys in the final exam can be calculated by subtracting the girls' score from the total score: \(50x + 250 - (30x + 60) = 20x + 190\). The average score of boys in the final exam is \(\frac{20x + 190}{20} = x + 9.5\).
The increase in the average score of the boys is \(x + 9.5 - x = 9.5\).
Thus, the increase in the average score of the boys is 9.5.
What is the sum of ages of Murali and Murugan?
Statements: I. Murali is 5 years older than Murugan.
Statements: II. The average of their ages is 25