It is given that,
Total students = 100
Girls = 25, Boys = 75
Rich = 20
Poor = 80
Fair complexion = 40, Dark = 60
Probability of selecting:
a girl = \(\frac{25}{100}\)
= \(\frac{1}{4}\)
a rich person = \(\frac{20}{100}\)
= \(\frac{1}{5}\)
a fair person = \(\frac{40}{100}\)
= \(\frac{2}{5}\)
Therefore, Probability of selecting a fair complexioned rich girl is
= \(\frac{1}{4}\times1\times5\times\frac{2}{5}\)
= \(0.02\)
Four students of class XII are given a problem to solve independently. Their respective chances of solving the problem are: \[ \frac{1}{2},\quad \frac{1}{3},\quad \frac{2}{3},\quad \frac{1}{5} \] Find the probability that at most one of them will solve the problem.
