It is given that,
Total students = 100
Girls = 25, Boys = 75
Rich = 20
Poor = 80
Fair complexion = 40, Dark = 60
Probability of selecting:
a girl = \(\frac{25}{100}\)
= \(\frac{1}{4}\)
a rich person = \(\frac{20}{100}\)
= \(\frac{1}{5}\)
a fair person = \(\frac{40}{100}\)
= \(\frac{2}{5}\)
Therefore, Probability of selecting a fair complexioned rich girl is
= \(\frac{1}{4}\times1\times5\times\frac{2}{5}\)
= \(0.02\)
If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :
