Surface area of the tent \(=2\pi rh+\pi rl\)
\(=\pi r(2h+1)\)
\(=\frac{22}{7}×70(2×3+80)\)
\(=18920\)
Width of the canvas \(=2m\)
∴Length of the Canvas required to make the tent \(=\frac{18920}{2}=9460\) m
Hence, option C is the correct answer. The correct option is (C): 9460 m
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$