Question:
A charged sphere (radius r, surface charge density σ) has electric field E. If the radius doubles (charge density constant), what's the ratio of the old to new electric field?
A charged sphere (radius r, surface charge density σ) has electric field E. If the radius doubles (charge density constant), what's the ratio of the old to new electric field?
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Electric field depends on charge density, not radius.
Updated On: Jan 13, 2026
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The Correct Option is A
Solution and Explanation
E = σ/ϵ₀. Electric field is independent of radius if charge density is constant. Therefore, the ratio is 1.
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