Total flux passing through the close cube \(ϕ = \frac {q}{ε_0}\)
All six surfaces exhibit symmetry with respect to the charge, resulting in an equal contribution to the flux. Consequently, the flux through any single face is:
\(ϕ = \frac ϕ 6 = \frac {q}{6ε_0}\)
\(φ_{face} = \frac {q}{6ε_0} = \frac {4\pi q}{6(4\piε_0)}\)
So, the correct option is (B): \(\frac {4\pi q}{6(4πε_0)}\)
The magnitude of heat exchanged by a system for the given cyclic process ABC (as shown in the figure) is (in SI units):

As shown below, bob A of a pendulum having massless string of length \( R \) is released from \( 60^\circ \) to the vertical. It hits another bob B of half the mass that is at rest on a frictionless table in the center. Assuming elastic collision, the magnitude of the velocity of bob A after the collision will be (take \( g \) as acceleration due to gravity):


Gauss law states that the total amount of electric flux passing through any closed surface is directly proportional to the enclosed electric charge.
According to the Gauss law, the total flux linked with a closed surface is 1/ε0 times the charge enclosed by the closed surface.

For example, a point charge q is placed inside a cube of edge ‘a’. Now as per Gauss law, the flux through each face of the cube is q/6ε0.
As per the Gauss theorem, the total charge enclosed in a closed surface is proportional to the total flux enclosed by the surface. Therefore, if ϕ is total flux and ϵ0 is electric constant, the total electric charge Q enclosed by the surface is;
Q = ϕ ϵ0
The Gauss law formula is expressed by;
ϕ = Q/ϵ0
Where,
Q = total charge within the given surface,
ε0 = the electric constant.