Step 1: Understanding the Motion of the Charged Particle
A charged particle moving in a magnetic field experiences a force given by: \[ F = q \vec{v} \times \vec{B} \] Where:
\(q\) is the charge of the particle,
\(\vec{v}\) is the velocity of the particle,
\(\vec{B}\) is the magnetic field.
The force due to the magnetic field is always perpendicular to the velocity of the particle.
Step 2: Analyzing the Components of Velocity
When the velocity has a component parallel to the magnetic field \( B \), the particle will experience no force along that direction, and will continue to move in the same direction.
When there is a component of velocity perpendicular to the magnetic field, the particle will experience a force and undergo circular motion in a plane perpendicular to the magnetic field.
The combination of these two components of velocity (along and perpendicular to the magnetic field) results in a helical motion. The particle moves in a spiral path around the magnetic field lines.
Step 3: Conclusion
The path of the charge particle will be a helical path with the axis along the direction of the magnetic field. This is because the component of velocity along \( B \) causes the particle to move parallel to the field, while the perpendicular component causes circular motion around the field lines.
Final Answer: The path of the charge particle will be a helical path with the axis along magnetic field \( B \).
Draw the pattern of the magnetic field lines for the two parallel straight conductors carrying current of same magnitude 'I' in opposite directions as shown. Show the direction of magnetic field at a point O which is equidistant from the two conductors. (Consider that the conductors are inserted normal to the plane of a rectangular cardboard.)
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Choke coil is simply a coil having a large inductance but a small resistance. Choke coils are used with fluorescent mercury-tube fittings. If household electric power is directly connected to a mercury tube, the tube will be damaged.
Reason (R): By using the choke coil, the voltage across the tube is reduced by a factor \( \frac{R}{\sqrt{R^2 + \omega^2 L^2}} \), where \( \omega \) is the frequency of the supply across resistor \( R \) and inductor \( L \). If the choke coil were not used, the voltage across the resistor would be the same as the applied voltage.
In light of the above statements, choose the most appropriate answer from the options given below:
Figure shows a current carrying square loop ABCD of edge length is $ a $ lying in a plane. If the resistance of the ABC part is $ r $ and that of the ADC part is $ 2r $, then the magnitude of the resultant magnetic field at the center of the square loop is: 