Let the number be \( N \). We are given that:
\[
N = 899k + 63,
\]
for some integer \( k \). Now, we want to find the remainder when \( N \) is divided by 29. First, reduce 899 modulo 29:
\[
899 \div 29 = 31 \text{ (quotient)} \quad \text{and} \quad 899 - 29 \times 31 = 899 - 899 = 0.
\]
Thus, \( 899 \equiv 0 \, (\text{mod} \, 29) \). Hence:
\[
N = 899k + 63 \equiv 0k + 63 \equiv 63 \, (\text{mod} \, 29).
\]
Now, reduce 63 modulo 29:
\[
63 \div 29 = 2 \quad \text{(quotient)} \quad \text{and} \quad 63 - 29 \times 2 = 63 - 58 = 5.
\]
Thus, the remainder when \( N \) is divided by 29 is 5.