Question:

A certain household has consumed \(250\) \(units\) of energy during a month. How much energy is this in joules?

Updated On: Nov 21, 2023
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Solution and Explanation

Energy consumed by a certain household = \(250\) \(kWh\)
since \(1\) \(kWh\) = \(3.6 × 10^6 \;J\)
therefore \(250\) \(kWh\) 
\(250 × 3.6 × 10^6\) 
\(9 × 108\)  \(J\).

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Concepts Used:

Work-Energy Theorem

The work and kinetic energy principle (also known as the work-energy theorem) asserts that the work done by all forces acting on a particle equals the change in the particle's kinetic energy. By defining the work of the torque and rotational kinetic energy, this definition can be extended to rigid bodies.

The change in kinetic energy KE is equal to the work W done by the net force on a particle is given by,

W = ΔKE = ½ mv2f − ½ mv2i

Where, 

vi → Speeds of the particle before the application of force

vf → Speeds of the particle after the application of force

m → Particle’s mass

Note: Energy and Momentum are related by, E = p2 / 2m.