Step 1: Extract Grade III proportions.
From the pie charts:
- Universities in Grade III = 7% of 504
- Colleges in Grade III = 23% of 25951
Step 2: Calculate actual numbers. \[ \text{Universities (Grade III)} = \frac{7}{100} \times 504 = 35.28 \approx 35 \] \[ \text{Colleges (Grade III)} = \frac{23}{100} \times 25951 = 5968.73 \approx 5969 \] So, total in Grade III = \(35 + 5969 = 6004\).
Step 3: Find total institutions. \[ \text{Total institutions} = 504 + 25951 = 26455 \]
Step 4: Calculate percentage. \[ % = \frac{6004}{26455} \times 100 \] \[ = 22.7% \text{(approx from earlier rough calc)} \] But recalculating with more precision: \[ \frac{6004}{26455} \times 100 = 22.7 % \] Wait — but carefully recomputing: \[ \frac{35.28 + 5968.73}{26455} \times 100 = \frac{6004.01}{26455} \times 100 = 22.7 % \] However, question asks "correct to one decimal place." Thus, final = **22.7%** \[ \boxed{22.7 %} \]
In a sequence of numbers, each term is generated by multiplying the previous term by 2 and then subtracting 1. If the first term is 3, what is the fourth term in the sequence?
A pie chart shows the distribution of students across 5 faculties in a university. If 20% are in Arts, 25% in Science, 15% in Law, 30% in Engineering, and the rest in Commerce, what is the angle (in degrees) for Commerce?
The table given below provides the details of monthly sales (in lakhs of rupees) and the value of products returned by the customers (as a percentage of sales) of an e-commerce company for three product categories for the year 2024. Net sales (in lakhs of rupees) is defined as the difference between sales (in lakhs of rupees) and the value of products returned (in lakhs of rupees).

P and Q play chess frequently against each other. Of these matches, P has won 80% of the matches, drawn 15% of the matches, and lost 5% of the matches.
If they play 3 more matches, what is the probability of P winning exactly 2 of these 3 matches?