Question

A Carnot engine operating between temperatures \( T_H = 600\,K \) and \( T_C = 300\,K \), absorbs \( Q_H = 800 \, \text{J} \) of heat from the source. The mechanical work done per cycle is:

• A. \( 400 \, \text{J} \)
• B. \( 650 \, \text{J} \)
• C. \( 750 \, \text{J} \)
• D. \( 600 \, \text{J} \)

Hint:

Carnot efficiency depends only on temperatures: \( \eta = 1 - \frac{T_C}{T_H} \). Multiply by absorbed heat to get work output.

Answer 1

The Correct Option is A

Efficiency of Carnot engine: \[ \eta = 1 - \frac{T_C}{T_H} = 1 - \frac{300}{600} = 0.5 \] Work done per cycle: \[ W = \eta \cdot Q_H = 0.5 \cdot 800 = 400 \, \text{J} \]