Question:
A car starts from rest and accelerates uniformly to a speed of $180\,km/h$ in $10\,s$. The distance covered by the car in this time interval is
A car starts from rest and accelerates uniformly to a speed of $180\,km/h$ in $10\,s$. The distance covered by the car in this time interval is
Updated On: Jun 8, 2024
- 500 m
- 250 m
- 100 m
- 200 m
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The Correct Option is B
Solution and Explanation
Speed, v = 180 $kmh^{-1}$ =50 $ms ^{-1}$ times t =10s
sence Acceleration of the car a =$\frac{v-u}{t}=\frac{50-0}{10}$
$5 ms^{-2}$
Thus the distance covered by the car
$S=\frac{1}{2}at^2=\frac{1}{2}\times 5\times (10)^2$ =250 m
sence Acceleration of the car a =$\frac{v-u}{t}=\frac{50-0}{10}$
$5 ms^{-2}$
Thus the distance covered by the car
$S=\frac{1}{2}at^2=\frac{1}{2}\times 5\times (10)^2$ =250 m
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.