Question:

A car, starting from rest, accelerates at the rate f through a distance S, then continues at: constant speed for time t and then decelerate at the rate $\frac{f}{2}$ to come to rest. If the total distance travelled is 15S, then

Updated On: Jul 5, 2022
  • $S= f t$
  • $S=\frac{1}{6}ft^2$
  • $S=\frac{1}{72}ft^2$
  • $S=\frac{1}{4}ft^2$
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The Correct Option is C

Solution and Explanation

$\frac{1}{2} \, ft^2_1 = s $ $f_2 = f /2 \, \Rightarrow \, S_2 = 2s v$ $\nu = ft_1 \, \Rightarrow \, t_1 = \frac{12S}{ft}$ & $S = \frac{1}{2} ft^2_1$
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Concepts Used:

Motion in a straight line

The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion. 

Types of Linear Motion:

Linear motion is also known as the Rectilinear Motion which are of two types:

  1. Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
  2. Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.