Question:
A car of mass 1500 kg is moving with 20 ms\(^{-1}\) velocity. If the breaks are applied it comes to rest in 5 seconds, then the retarding force is
A car of mass 1500 kg is moving with 20 ms\(^{-1}\) velocity. If the breaks are applied it comes to rest in 5 seconds, then the retarding force is
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When calculating the retarding force, use the equation of motion to first determine the acceleration (or deceleration), and then apply Newton's second law to find the force.
Updated On: May 15, 2025
- \( 9000 \, \text{N} \)
- \( 6000 \, \text{N} \)
- \( 12000 \, \text{N} \)
- \( 3000 \, \text{N} \)
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The Correct Option is B
Solution and Explanation
We are given that the car is moving with an initial velocity of \( 20 \, \text{m/s} \), the mass of the car is \( 1500 \, \text{kg} \), and the time taken to come to rest is \( 5 \, \text{seconds} \).
The retardation force is calculated using the equation of motion:
\[
F = ma
\]
Where \( a \) is the acceleration (deceleration in this case), which can be found using the formula:
\[
a = \frac{\Delta v}{t} = \frac{0 - 20}{5} = -4 \, \text{m/s}^2
\]
Now, applying Newton's second law:
\[
F = ma = 1500 \times (-4) = -6000 \, \text{N}
\]
Thus, the retarding force is \( 6000 \, \text{N} \).
Hence, the correct answer is option (2).
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