Question:

A car covers the first one-third of a distance x at a speed of $10\, km\, h^{-1}$, the second one-third at a speed of $20\, km\, h^{-1}$ and the last one-third at a speed of $60\, km \,h^{-1}$. Find the average speed of the car over the entire distance x.

Updated On: Jul 5, 2022
  • $10\, km\, h^{-1}$
  • $12\, km\, h^{-1}$
  • $18\, km\, h^{-1}$
  • $20\, km\, h^{-1}$
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The Correct Option is C

Solution and Explanation

For first one-third of distance Distance covered $= \frac{x}{3} \,km$ Speed $= 10\,km\, h^{-1}.$ The time taken for the journey, $t_{1} = \frac{x/3}{10} h = \frac{x}{30} h$ For the next one-third of distance : Distance covered $= \frac{x}{3} km$ Speed $= 20\, km\, h^{-1}.$ The time taken for travel is $t_{2} = \frac{x/3}{20} h = \frac{x}{60} h$ For the last one-third of distance : Distance covered $= \frac{x}{3} \,km$ Speed $= 60 \,km\, h^{-1}.$ The time taken for travel is $t_{3} = \frac{x/3}{60} h = \frac{x}{180} h$ $\therefore\quad$ Average Speed $= \frac{total \,distance}{total\, time} = \frac{x}{\frac{x}{30}+\frac{x}{60}+\frac{x}{180}}$ $= \frac{180x}{10x} = 18\, km\, h^{-1}$
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Concepts Used:

Motion in a straight line

The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion. 

Types of Linear Motion:

Linear motion is also known as the Rectilinear Motion which are of two types:

  1. Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
  2. Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.