Question:

A capacitor of capacity C and reactance X if capacitance and frequency become double then

Updated On: Aug 16, 2024
  • 4X
  • X/2
  • X/4
  • 2X
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The Correct Option is C

Solution and Explanation

The correct option is(C): X/4 The capacitive reactance is determined by the formula: X = 1 / (ωC) = 1 / (2πfC) Here,C represents the capacitance,f represents the frequency. Now, when both the frequency and capacitance are doubled: X' = 1 / [2π(2f)(2C)] = 1 / (4πfC) This simplifies to: X' = (1/4) * (1 / (2πfC)) = (1/4) * X = (X / 4)
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Questions Asked in NEET exam

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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter