Question:

A can complete a piece of work in 18 days. B is 20\% more efficient than A. The number of days B takes to complete the same piece of work is?

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When one person is more efficient than another, use their efficiency multiplier to calculate the time taken.
Updated On: Apr 28, 2025
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The Correct Option is A

Solution and Explanation


A completes the work in 18 days, so A's work rate is \( \frac{1}{18} \) of the work per day. B is 20\% more efficient, so B's rate is \( (1)2 \times \frac{1}{18} = \frac{(1)2}{18} \). The time taken by B to complete the work is the reciprocal of B's rate: \[ \text{Time taken by B} = \frac{1}{\frac{(1)2}{18}} = \frac{18}{(1)2} = 15 \text{ days}. \]
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