Question:

A boy stands on a weighing machine inside a lift. When the lift is going down with acceleration $g/4$, the machine shows a reading $30 \,kgf$. When the lift goes upwards with acceleration $g/4$, the reading would be

Updated On: Jul 5, 2022
  • 18 kgf
  • 37.5 kgf
  • 50 kgf
  • 67.5 kgf
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

While going down, machine reading is 30 kgf. $\Rightarrow\quad mg-N=m\left(\frac{g}{4}\right);$ $mg-30g=\frac{mg}{4}\,;3 \frac{mg}{4}=30g$ $m=\frac{30\times4}{3}=40\,kg$ While going up, the reaction would be $N^{'}-mg=m \frac{g}{4}$ $N^{'}=5 \frac{mg}{4}=\frac{5}{4}\,\left(40\,kg\right)g$ $\Rightarrow\quad N^{'}=50 \,kgf.$
Was this answer helpful?
0
0

Top Questions on laws of motion

View More Questions

Questions Asked in AIIMS exam

View More Questions

Concepts Used:

Laws of Motion

The laws of motion, which are the keystone of classical mechanics, are three statements that defined the relationships between the forces acting on a body and its motion. They were first disclosed by English physicist and mathematician Isaac Newton.

Newton’s First Law of Motion

Newton’s 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.

Newton’s Second Law of Motion

Newton's 2nd law of motion deals with the relation between force and acceleration. According to the second law of motion, the acceleration of an object as built by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Newton’s Third Law of Motion

Newton's 3rd law of motion states when a body applies a force on another body that there is an equal and opposite reaction for every action.