Let's denote the number of white balls as \( W \) and the number of black balls as \( B \).
From the information given:
We are told that the number of metallic white balls is equal to the number of metallic black balls, so:
\[ 0.40W = 0.50B \quad \text{... (i)} \]
\p>The total number of balls is given as \( W + B = 450 \), which is:
\[ W + B = 450 \quad \text{... (ii)} \]
From equation (i), we can express \( W \) in terms of \( B \):
\[ W = \frac{5}{4}B \quad \text{... (iii)} \] Substituting this into equation (ii): \[ \left(\frac{5}{4}\right)B + B = 450 \] \[ \frac{(5B + 4B)}{4} = 450 \quad \Rightarrow \quad \frac{9B}{4} = 450 \] \[ 9B = 1800 \quad \Rightarrow \quad B = 200 \]
Since \( B = 200 \), we can substitute this back into equation (iii) to find \( W \): \[ W = \frac{5}{4} \times 200 = 250 \]
Now, using the percentage of metallic balls: \[ \text{Metallic white balls} = 0.40 \times 250 = 100 \] \[ \text{Metallic black balls} = 0.50 \times 200 = 100 \]
The number of non-metallic balls is calculated as: \[ \text{Non-metallic white balls} = 250 - 100 = 150 \] \[ \text{Non-metallic black balls} = 200 - 100 = 100 \]
The total number of non-metallic balls is: \[ 150 + 100 = 250 \]
The box contains \( \boxed{250} \) non-metallic balls.
Let the number of white balls = \( x \)
Let the number of black balls = \( y \)
Total number of balls: \[ x + y = 450 \tag{1} \]
Given: \[ 0.4x = 0.5y \Rightarrow 4x = 5y \Rightarrow 4x - 5y = 0 \tag{2} \]
From Eq. (1): \( y = 450 - x \)
Substitute into (2): \[ 4x - 5(450 - x) = 0 \Rightarrow 4x - 2250 + 5x = 0 \Rightarrow 9x = 2250 \Rightarrow x = 250 \Rightarrow y = 450 - 250 = 200 \]
Total non-metallic balls: \[ 150 + 100 = \boxed{250} \]
Final Answer: 250
When $10^{100}$ is divided by 7, the remainder is ?