Total ways to choose 2 socks from 9:
\(\binom{9}{2} = 36\)
Ways to choose 2 brown socks:
\(\binom{5}{2} = 10\)
Ways to choose 2 white socks:
\(\binom{4}{2} = 6\)
Total favorable outcomes (same color):
\(10 + 6 = 16\)
Probability of same color socks:
\(\frac{16}{36} = \frac{4}{9}\)
The probability that the two socks are of the same color is \(\frac{4}{9}\).
List-I | List-II (Adverbs) |
(A) P(exactly 2 heads) | (I) \(\frac{1}{4}\) |
(B) P(at least 1 head) | (II) \(1\) |
(C) P(at most 2 heads) | (III) \(\frac{3}{4}\) |
(D) P(exactly 1 head) | (IV) \(\frac{1}{2}\) |
LIST-I(EVENT) | LIST-II(PROBABILITY) |
(A) The sum of the number is greater than 11 | (i) 0 |
(B) The sum of the number is 4 or less | (ii) 1/15 |
(C) The sum of the number is 4 | (iii) 2/15 |
(D) The sum of the number is 4 | (iv) 3/15 |
Choose the correct answer from the option given below