Question:
A box contains 3 red, 4 yellow and \((x+1)\) green balls. If two balls are taken out, then the probability that both the balls being green is \(\frac {5}{33}\). Find the value of x?
A box contains 3 red, 4 yellow and \((x+1)\) green balls. If two balls are taken out, then the probability that both the balls being green is \(\frac {5}{33}\). Find the value of x?
Updated On: Oct 24, 2024
- 3
- 4
- 2
- 1
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The Correct Option is B
Solution and Explanation
The correct option is (B): 4.
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