Question:
A box contains 100 tickets numbered 00,01,02,....99 and a ticket is drawn at random. Let X denote the sum of the digits on that ticket and Y denote the product of those digits. Then the value of P(X=2IY=0) is
A box contains 100 tickets numbered 00,01,02,....99 and a ticket is drawn at random. Let X denote the sum of the digits on that ticket and Y denote the product of those digits. Then the value of P(X=2IY=0) is
Updated On: Jun 10, 2024
- \(\frac{3}{19}\)
- \(\frac{6}{19}\)
- \(\frac{1}{19}\)
- \(\frac{2}{19}\)
- \(\frac{1}{100}\)
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The Correct Option is D
Solution and Explanation
The correct option is (D): \(\frac{2}{19}\)
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