Question:
A body starts to fall freely under gravity. The distance covered by it in first, second and third second are in ratio
A body starts to fall freely under gravity. The distance covered by it in first, second and third second are in ratio
Updated On: Jun 7, 2024
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The Correct Option is A
Solution and Explanation
Distance covered in $n^{\text {th }}$ sec.
$ s_{n}=u+\frac{a}{2}(2 n-1) $
$\because$ $u=0$
So, $s_{n}=\frac{a}{2}(2 n-1)$, $a$ is constant
Therefore, $s_{1}: s_{2}: s_{3}$
$=\{2(1)-1\}:\{2(2)-1\}:\{2(3)-1\}$
$=1: 3: 5$
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.