A body of weight 200 N is suspended from a tree branch through a chain of mass 10 kg. The branch pulls the chain by a force equal to (if $g = 10 \, \text{m/s}^2$):
- 150 N
- 300 N
- 200 N
- 100 N
The Correct Option is B
Solution and Explanation
The total weight acting on the chain is the sum of the weight of the body and the weight of the chain itself.
1. Weight of the body: \( 200 \, \text{N} \)
2. Weight of the chain: \( 10 \times 10 = 100 \, \text{N} \)
Thus, the total weight is:
\[\text{Total weight} = 200 + 100 = 300 \, \text{N}\]
Since the chain-block system is in equilibrium, the tension \( T \) in the chain must balance the total weight:
\[T = 300 \, \text{N}\]
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