$m=5\,Kg$, $\alpha=10$ rad $s^{-2}$, $\tau=2\,N\,m$ Torque, $\tau=I \alpha=mk^{2}\alpha \left(\because I=mk^{2}\right)$ where $k$ is the radius of gyration $\therefore 2=5\times k^{2}\times10$ or $k^{2}=0.04$ or $k=0.2\,m$
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Top Questions on System of Particles & Rotational Motion
The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.