A body of mass 0.5 kg travels in a straight line with velocity v =a x 3/2 where a = 5 m−1/2 s–1 . What is the work done by the net force during its displacement from x = 0 to x = 2 m ?
Mass of the body, m = 0.5 kg Velocity of the body is governed by the equation, v = a x3/2 with a = 5 m −1/2 s - 1 Initial velocity, u (at x = 0) = 0 Final velocity v (at x = 2 m) = 102m/s Work done, W = Change in kinetic energy = 21 m(v2 - u2) = 21× [(102)2 - (0)2] = 21 × 0.5 × 10 × 10 × 2 = 50 J