Question:

A body is released from a great height falls freely towards the earth. Another body is released from the same height exactly a second latter. Then the separation between two bodies, $2\,s$ after the release of the second body is, nearly

Updated On: May 15, 2024
  • 15 m
  • 20 m
  • 25 m
  • 30 m
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The Correct Option is C

Solution and Explanation

$s=u t+\frac{1}{2} a t^{2}$
For 1st body $u =0$ and a $= g$ (freely falling body)
Distance covered in $2\, s$
$s_{1}=0+\frac{1}{2} g(2)^{2}$
For 2 nd body Distance covered in $2\, s$
$s_{2}=0+\frac{1}{2} g(3)^{2}$
hence $s_{2}-s_{1}=\frac{1}{2} g\left[(3)^{2}-(2)^{2}\right]$
$=\frac{1}{2} g[9-4]$
$=25\, m$
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