Question:
A body is projected vertically upwards. The times corresponding to height h while ascending and while descending are \(t_1\) and \(t_2\), respectively. Then, the velocity of projection will be
(take g as acceleration due to gravity)
A body is projected vertically upwards. The times corresponding to height h while ascending and while descending are \(t_1\) and \(t_2\), respectively. Then, the velocity of projection will be
(take g as acceleration due to gravity)
(take g as acceleration due to gravity)
Updated On: Jun 21, 2024
- \(\frac {g \sqrt {t_1t_2}}{2}\)
- \(\frac {g(t_1+t_2)}{2}\)
- \(g \sqrt {t_1t_2}\)
- \(g \frac {t_1t_2}{(t_1+t_2)}\)
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
The correct option is (B): \(\frac {g(t_1+t_2)}{2}\).
Was this answer helpful?
0
0
Top Questions on Motion in a straight line
- A ball is dropped from a height of 20 m. What is its velocity just before hitting the ground? (Take \( g = 9.8 \, \text{m/s}^2 \))
- VITEEE - 2025
- Physics
- Motion in a straight line
- A body is falling freely under gravity from a certain height from the ground. If the sum of the displacements of the body in the second and third seconds of its motion is 32% of the height from which it is falling, then the speed with which the body hits the ground is (Acceleration due to gravity = $10~\text{m s}^{-2}$)
- TS EAMCET - 2025
- Physics
- Motion in a straight line
- A motor cyclist is travelling towards north with a uniform speed of 10 ms\textsuperscript{−1} and a train is travelling towards north-west with a uniform speed of 102 ms\textsuperscript{−1}. The direction of motion of the motor cyclist as observed by a passenger in the train is
- TS EAMCET - 2025
- Physics
- Motion in a straight line
- A car accelerates uniformly from rest to a velocity of \( 25 \, \text{m/s} \) in \( 10 \, \text{seconds} \). What is the acceleration of the car?
- MHT CET - 2025
- Physics
- Motion in a straight line
- A particle initially at rest is moving along a straight line with an acceleration of 2 ms⁻². At a time of 3 s after the beginning of motion, the direction of acceleration is reversed. The time from the beginning of the motion in which the particle returns to its initial position is
- TS EAMCET - 2025
- Physics
- Motion in a straight line
View More Questions
Questions Asked in JIPMER MBBS exam
- Find resonance frequency in the given circuit:
- JIPMER MBBS - 2019
- Resonance
- A particle is moving with 10 m/s in a circle of radius 5m, find out magnitude of average velocity if particle moved by 60° in 1 sec.
- JIPMER MBBS - 2019
- Average velocity and average speed
- If equilibrium constant is 2.6×108 then find the value of ΔG°.
- JIPMER MBBS - 2019
- Thermodynamics
- In the given circuit, find voltage across 12 Ω resistance.
- JIPMER MBBS - 2019
- Electric Circuit
- Speed of particles at 3rd and 8th seconds are 20 m/s are zero respectively. Then average acceleration between 3rd and 8th second will be -
- JIPMER MBBS - 2019
- Kinematics
View More Questions