Question:
A body is projected vertically upwards. The times corresponding to height h while ascending and while descending are \(t_1\) and \(t_2\), respectively. Then, the velocity of projection will be
(take g as acceleration due to gravity)
A body is projected vertically upwards. The times corresponding to height h while ascending and while descending are \(t_1\) and \(t_2\), respectively. Then, the velocity of projection will be
(take g as acceleration due to gravity)
(take g as acceleration due to gravity)
Updated On: Jun 21, 2024
- \(\frac {g \sqrt {t_1t_2}}{2}\)
- \(\frac {g(t_1+t_2)}{2}\)
- \(g \sqrt {t_1t_2}\)
- \(g \frac {t_1t_2}{(t_1+t_2)}\)
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The Correct Option is B
Solution and Explanation
The correct option is (B): \(\frac {g(t_1+t_2)}{2}\).
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