The power delivered to a body is the rate at which work is done, and it can be expressed as: \[ P = F \cdot v \] Where:
\( P \) is the power,
\( F \) is the force,
\( v \) is the velocity.
For a body undergoing motion with constant acceleration, the velocity at any time \( t \) is given by: \[ v = at \] Where \( a \) is the constant acceleration. The force acting on the body is given by Newton's second law: \[ F = ma \] Where \( m \) is the mass of the body and \( a \) is the acceleration. Substituting the expressions for \( F \) and \( v \) into the equation for power: \[ P = ma \cdot at = ma^2 t \] Since the body starts from rest and has constant acceleration, the power delivered to the body is proportional to \( t \).
Thus, the power delivered to the body at time \( t \) is proportional to \( t \).
The correct answer is (B) : t.
If the voltage across a bulb rated 220V – 60W drops by 1.5% of its rated value, the percentage drop in the rated value of the power is: